The value of Bohr magneton, $μ_{B}$ is

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$9 .27 \times 10^{- 24} {Am}^{2}$

$9 .27 \times 10^{- 22} {Am}^{2}$

$11 .27 \times 10^{- 22} {Am}^{2}$

$11 .27 \times 10^{- 24} {Am}^{2}$

answer is A.

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Detailed Solution

The value of Bohr magneton, $μ_{B} is 9 .27 \times 10^{- 24} {Am}^{2}$

The correct option is B: 9.27 x 10^-24 Am²

Bohr Magnetron

(μl)_min = μ_s = e × h / 4π × m_e

Here,
e = 1.6 X 10^-19 C,
h = 6.64 X 10^-34 J·s,
m_e = 9.1 X 10^-31 kg

μ_B = (1.60 × 10^-19 × 6.64 × 10^-34) / (4 × 3.14 × 9.1 × 10^-31) = 9.27 X 10^-24 Am²

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