The value of Bohr magneton, ${\mathrm{\mu }}_{\mathrm{B}}$ is

The value of Bohr magneton,${\mathrm{\mu }}_{\mathrm{B}}\text{ is }9.27\times {10}^{-24}{\mathrm{Am}}^2$

The correct option is B: 9.27 x 10^-24 Am²

Bohr Magnetron

(μl)_min = μ_s = e × h / 4π × m_e

Here, 
e = 1.6 X 10^-19 C, 
h = 6.64 X 10^-34 J·s, 
m_e = 9.1 X 10^-31 kg

μ_B = (1.60 × 10^-19 × 6.64 × 10^-34) / (4 × 3.14 × 9.1 × 10^-31) = 9.27 X 10^-24 Am²