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Q.

The value of 'c' in Lagrange's mean value theorem for f(x)=(x−a)m(x−b)n in [a,b] is

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a

mb+nam+n

b

ma+nbm+n

c

a+bm+n

d

a+b2

answer is A.

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Detailed Solution

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By Lagrange's theorem, f′(c)=f(b)−f(a)b−a⇒c=mb+nam+n

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