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Q.

The value of 'c' in Lagrange's mean value theorem for f(x)=(xa)m(xb)n in [a,b] is

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a

ma+nbm+n

b

a+b2

c

a+bm+n

d

mb+nam+n

answer is A.

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Detailed Solution

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By Lagrange's theorem, f(c)=f(b)f(a)bac=mb+nam+n

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