The value of CFSE for ${\left[\mathrm{Ti}{\left({\mathrm{H}}_2\mathrm{O}\right)}_6\right]}^{2+}$ complex $\mathrm{n}\times {10}^{-1}{\mathrm{\Delta }}_0$ . The value of n will be _______

 ${\left[\mathrm{Ti}{\left({\mathrm{H}}_2\mathrm{O}\right)}_6\right]}^{2+}$is a 3d² system. In an octahedral system, there are three $\left({\mathrm{d}}_{\mathrm{xy}},{\mathrm{d}}_{\mathrm{yz}},{\mathrm{d}}_{\mathrm{xz}}\right)$ lower
energy levels with energy $-0.4\mathrm{\Delta }G\left({\text{ in kJ mol }}^{-1}\right).$ As only two of these energy levels of $t_{2g}$ are occupied, 
so, CFSE $=2\left(-0.4{\mathrm{\Delta }}_0\right)=-0.8{\mathrm{\Delta }}_0$ 
Hence, $n\times {10}^{-1}{\mathrm{\Delta }}_0=8\times {10}^{-1}{\mathrm{\Delta }}_0\therefore n=8$