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Q.

The value of cos 2π7+cos 4π7+cos 6π7 is equal to :

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a

-1
 

b

-12
 

c

-14

d

-13
 

answer is B.

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Detailed Solution

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cos2π7+cos4π7+cos6π7cosα+cosα+β+cos(α+2β)+....cosα+n-1β=sinnβ2sinβ2cosα+n-1β2=sin3×π7sinπ7×cos2π7+6π72 =2sin3π72sinπ7×cos4π7 =sin7π7+sin-π72sinπ7 =-sinπ72sinπ7=-12Option B is correct

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