The value of current in the following diagram will be (assume the diode is ideal )

$$\begin{gathered} Diode is connected in forward bia\sin g and hence behaves like conducting wire. \\ Apply Ohm\text{'}s Law : \end{gathered}$$

$I = \frac{V}{R} = \frac{(5-3)}{200} = {10}^{-2}A$