Q.

The value of equilibrium constant of a reaction changes with change of temperature and the change is given by van’t Hoff equation,  dlnKpdT=ΔH°RT2,  where enthalpy change, ΔH°  is taken as constant in the small temperature range. If for reaction, A(g)+3B(g)2C(g),    a plot of ln Keq versus  1/T  is shown, then which of the following condition will be favorable for formation of  product C?

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a

Low temperature and low pressure

b

Low temperature and high pressure

c

High temperature and low pressure

d

High temperature and high pressure

answer is B.

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Detailed Solution

Since slope is negative hence reaction is endothermic. So high temperature favors forward reaction similarly high pressure favors forward reaction.

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