The value of force of gravity on a boy of mass 40 kg was found to be 391 N. Mass of the earth is 6×1024 kg, radius of the earth is 6.4×106 m. Which of the following is the value of gravitational constant G from the given data?

The value of gravitational constant G with the above details is 6.673×10-11 Nm2kg-2.As per Newton's universal law of gravitation we know that force of attraction between 2 bodies is given by F=Gm1m2r2 G is the gravitational constant m1is the mass of first body m2 is the mass of the second body r is the distance between two bodies.Mass of earth M=6×1024kg Mass of the boy m=40 kgRadius of the earth r=6.4×106m Hence, the force of attraction between the boy and earth can be written as F=GMmr2----(i) F is given as 391 N⇒ 391 =G×6×1024 ×40 (6.4×106 )2 ⇒ 391 =G×240×1024 40.96×(106 )2 ⇒391×40.96×1012 =G×240×1024 ⇒ 391×40.96×1012240×1024 =G ⇒ 66.731012 =G ⇒ G=6.673×10-11 Nm2kg-2Thus, the value of gravitational constant G with the above details is 6.673×10-11 Nm2kg-2.

The value of force of gravity on a boy of mass 40 kg was found to be 391 N. Mass of the earth is 6×1024 kg, radius of the earth is 6.4×106 m. Which of the following is the value of gravitational constant G from the given data?

The value of gravitational constant G with the above details is 6.673×10-11 Nm2kg-2.As per Newton's universal law of gravitation we know that force of attraction between 2 bodies is given by F=Gm1m2r2 G is the gravitational constant m1is the mass of first body m2 is the mass of the second body r is the distance between two bodies.Mass of earth M=6×1024kg Mass of the boy m=40 kgRadius of the earth r=6.4×106m Hence, the force of attraction between the boy and earth can be written as F=GMmr2----(i) F is given as 391 N⇒ 391 =G×6×1024 ×40 (6.4×106 )2 ⇒ 391 =G×240×1024 40.96×(106 )2 ⇒391×40.96×1012 =G×240×1024 ⇒ 391×40.96×1012240×1024 =G ⇒ 66.731012 =G ⇒ G=6.673×10-11 Nm2kg-2Thus, the value of gravitational constant G with the above details is 6.673×10-11 Nm2kg-2.