The value of Henry's law constant for argon (Ar), carbon dioxide (CO₂), methane (CH₄) and formaldehyde (HCHO) are respectively 40.3 K bar,1.67 K bar, 0.413 K bar and
1.83 x 10^-5 K bar at 298 K.
The correct order of their solubility is

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$Ar < {CH}_{4} < {CO}_{2} < HCHO$

$Ar < {CO}_{2} < {CH}_{4} < HCHO$

$HCHO < {CH}_{4} < {CO}_{2} < Ar$

$Ar < {CO}_{2} < HCHO < {CH}_{4}$

answer is C.

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Detailed Solution

Higher the value of Henry's law constant, lower is the solubility of gas in water (or in liquid solvent).
The order of K_H value is:
$\begin{array}{lrcc} Ar & {CO}_{2} & {CH}_{4} & HCHO \\ 40.3 & > 1 .67 & > 0 .413 & > 1 .83 \times 10^{- 5} \end{array}$
Thus, the order of solubility is:
$Ar < {CO}_{2} < {CH}_{4} < HCHO$