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The value of $' k'$ , if the roots of the quadratic equation $k x (x - 2) + 6 = 0$ are equal

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Detailed Solution

k x (x - 2) + 6 = 0

are equal roots

$k x^{2} - 2 k x + 6 = 0$

$b^{2} = 4 a c$

$\Rightarrow {(- 2 k)}^{2} = 4 (k) (6)$

$\to 4 k^{2} - 4 k (6)$

$\to k = 6$

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