The value of kc for the reaction A2+B2⇌2AB is ‘x’. Then the value of kc for the reaction 12A2+12B2⇌AB is [at the same temperature]

A2+B2⇌2AB 12A2+12B2⇌AB12A2+12B2⇌AB, kc=ABA2.B2=x

The value of kc for the reaction A2+B2⇌2AB is ‘x’. Then the value of kc for the reaction 12A2+12B2⇌AB is [at the same temperature]

A2+B2⇌2AB 12A2+12B2⇌AB12A2+12B2⇌AB, kc=ABA2.B2=x

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The value of $k_{c}$ for the reaction $A_{2} + B_{2} ⇌ 2 AB$ is ‘x’. Then the value of $k_{c}$ for the reaction $\frac{1}{2} A_{2} + \frac{1}{2} B_{2} ⇌ A B$ is [at the same temperature]

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$x$

$\frac{x}{2}$

$2 x$

$\sqrt{x}$

answer is D.

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$A_{2} + B_{2} ⇌ 2 AB$ $\frac{1}{2} A_{2} + \frac{1}{2} B_{2} ⇌ AB$

$\frac{1}{2} A_{2} + \frac{1}{2} B_{2} ⇌ AB$ , $k_{c} = \frac{[AB]}{\sqrt{A_{2}} . \sqrt{B_{2}}} = \sqrt{x}$

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The value of kc for the reaction A2+B2⇌2AB is ‘x’. Then the value of kc for the reaction 12A2+12B2⇌AB is [at the same temperature]

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The value of $k_{c}$ for the reaction $A_{2} + B_{2} ⇌ 2 AB$ is ‘x’. Then the value of $k_{c}$ for the reaction $\frac{1}{2} A_{2} + \frac{1}{2} B_{2} ⇌ A B$ is [at the same temperature]