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Q.

The value of   limxπ221cos2x+31cos2x+41cos2x+51cos2x+61cos2x2cos2x

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a

36

b

1

c

136

d

6

answer is C.

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Detailed Solution

limxπ2(2(1cos2x)+3(1cos2x)+4(1cos2x)+5(1cos2x)+6(1cos2x))2cos2x

limxπ2(61cos2x)2cos2x(26(1cos2x)+36(1cos2x)+46(1cos2x)+56(1cos2x)+1)2cos2x

(61cos2x)2cos2x=62=36

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