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Q.

The value of m in order that x42x3+3x2mx+5 may be exactly divisible by x3is

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a

493

b

7

c

493

d

593

answer is D.

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Detailed Solution

p(x)=x42x3+3x2mx+5 is exactly divisible by x3

Then p(3)=342(3)3+3(3)2m(3)+5=0

8154+273m+5=0593m=0m=593

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