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The value of p for which the lines $2 x + y - 3 = 0, 3 x - y - 2 = 0$ and $x - p y + 5 = 0$ may intersect at a point is

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answer is D.

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Detailed Solution

First two lines intersect at (1, 1) and the third line passes through (1, 1) if $p = 6$

$Alternatively [\begin{array}{ccc} 1 & - p & 5 \\ 2 & 1 & - 3 \\ 3 & - 1 & - 2 \end{array}] = 0$

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