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Q.

The value of Planck constant is $6.63 \times 10^{- 34} J s$ he velocity of light is $3.0 \times 10^{7} m s^{- 1}$ . Which value is closest to the wavelength in nanometers of a quantum of light with frequency of $8 \times 10^{15} s^{- 1}$

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a

$4 \times 10^{1}$

b

$3 \times 10^{7}$

c

$2 \times 10^{- 25}$

d

$5 \times 10^{- 18}$

answer is A.

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Detailed Solution

$v = c / λ = \frac{3 \times 108}{8 \times 1015} = 37.5 \times 10^{9} m$

$= 37.5 n m \approx 4 \times 10^{1} n m$

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The value of Planck constant is 6.63×10−34Js he velocity of light is 3.0×107m s−1. Which value is closest to the wavelength in nanometers of a quantum of light with frequency of 8×1015s−1