Q.

The value of r for which  20Cr20C0+20Cr120C1+20Cr220C2+.20C020Cr is maximum, is

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a

11

b

10

c

20

d

15

answer is A.

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Detailed Solution

 20Cr20C0+20Cr120C1+20Cr220C2++20C020Cr

=coefficient of xr in (1+x)20(1+x)20

= coefficient of xr in (1+x)40

=40Cr  

 40Cr is maximum if r=20.

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