The value of r ms current for circuit shown in figure is 2.2 A. Then the CORRECT statement(s) is/are

 $I_{rms}=\frac{E_{rms}}{Z}$
 $2.2=\frac{220}{Z}$
 $Z=100\Omega$
Hence $X_L=X_C$  
$L\omega =\frac{1}{\omega C}$ 
$C=\frac{1}{W^{2}L}=\frac{1}{{\left(100\pi \right)}^2.\frac{1}{\pi }}=\frac{1}{{10}^4\pi }F=\frac{100}{\pi }\mu F$ 
$\because X_L=X_C$ 
Hence $\cos \varphi =\frac{R}{C}=1$  
$P=E_{rms}{I}_{rms}=220\times 2.2\times 10=484W$ 
After inductor is short circuits impedance $Z=100\sqrt{2}$
$\therefore I_{rms}=\frac{200}{100\sqrt{2}}=\left(\frac{2.2}{\sqrt{2}}\right)$