The value of rate constant of a reaction is 2.5 x10^-3 Lit mol^-1 sec^-1 . What is the rate of reaction if the concentration of reactant is 2 M.

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$2 .5 \times 10^{- 3}$

$5 \times 10^{- 3}$

$1 \times 10^{- 3}$

$1 \times 10^{- 2}$

answer is B.

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Detailed Solution

Unit of rate constant indicates it is second order reaction
$Rate = k (conc)^{2} = (2 .5 \times 10^{- 3}) \times (2)^{2} = 10 \times 10^{- 3} = 1 \times 10^{- 2}$

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