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Q.

The value of sin1(cos2)cos1(sin2)+tan1(cot(4))cot1(tan4)+sec1(cosec6)cosec1(sec6) is

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a

3π

b

5π-16

c

8-3π

d

0

answer is D.

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Detailed Solution

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sin1(cos2)=π2cos1(cos2)=π22cos1(sin2)=π2sin1(sin2)=π2sin1(sin(π2))=π2π+2=2π2tan1(cot4)=π2cot1(cot(4))=π2cot1(cot(4π))=π2(4π)=3π24cot1(tan4)=π2tan1(tan(4))=π2tan1(tan(4π))π2(4π)=3π24sec1(cosec6)=π2cosec(cosec6)=π2cosec1(cosec(62π))=π2(62π)=5π26cosec(sec6)=π2sec1(sec6)=π2sec1(sec(2π6))=π2(2π6)=3π2+6sin1(cos2)cos1(sin2)+tan1(cot4)cot1(tan4)+sec1(cosec6)cosec1(sec6)=π222+π2+3π243π2+4+5π26+3π26 =5π16

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