The value of $\tan 1 ° \tan 2 ° \tan 3 ° ........ \tan 89 °$ is

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$\frac{1}{2}$

answer is B.

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Detailed Solution

$\begin{array}{l} A + B = 90 ° \\ \tan A . \tan B = 1 \\ (\tan 1 ° . \tan 89 °) (\tan 2 ° \tan 88 °) ........... \tan 45 ° = 1.1.1....1 = 1 \end{array}$

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