The value of tension in a long thin metal wire has been changed from T₁ and T₂. The lengths of the metal wire at two different values of tension T₁ and T₂ are l₁ and l₂ respectively. The actual length of the metal wire is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

$\sqrt{T_{1} T_{2} l_{2} l_{2}}$

$\frac{T_{1} l_{2} - T_{2} l_{1}}{T_{1} - T_{2}}$

$\frac{l_{1} + l_{2}}{2}$

$\frac{T_{1} l_{1} - T_{2} l_{2}}{T_{1} - T_{2}}$

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

We know that,

$Y = \frac{F L}{A ∆ L}$

from the question,

$Y = \frac{T_{1} l_{0}}{A (l_{1} - l_{0})} = \frac{T_{2} l_{0}}{A (l_{2} - l_{0})} 1 = \frac{T_{1} (l_{2} - l_{0})}{T_{2} (l_{1} - l_{0})} T_{2} l_{1} - T_{2} l_{0} = T_{1} l_{2} - T_{1} l_{0} (T_{1} - T_{2}) l_{0} = T_{1} l_{2} - T_{2} l_{1} l_{0} = (\frac{T_{1} l_{2} - T_{2} l_{1}}{T_{1} - T_{2}})$