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The value of the derivative of |x1|+|x3| at x=2 is:

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a
2
b
-2
c
0
d
not defined

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detailed solution

Correct option is B

Let f(x) = I x- 1l + I x-3 I
At x= 2,
|x1|=x1 and |x3|=x+3f(x)=x1x+3=2
which is constant function.  f ' (2) = 0

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