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Q.

The value of the expression cosec (750+θ)-sec(150-θ)-tan(550+θ)+cot(350-θ), is ?


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a

-1

b

0

c

1

d

32  

answer is B.

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Detailed Solution

Given expression is, cosec (750+θ)-sec(150-θ)-tan(550+θ)+cot(350-θ).
Let the above expression be E.
We know that,
cosec θ=sec(900-θ) and tanθ=cot(900-θ).
By using the above trigonometric functions, we get
E=sec(900-750-θ)-sec(150-θ)-cot(900-550-θ)+cot(350-θ) ⇒E=secsec 150-θ -secsec 150-θ -cotcot 350-θ +cotcot 350-θ 
⇒E=0 Hence, the correct option is (2).
 
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