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Q.

The value of the expression 0ax4a2x2dx0ax2a2x2dx

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a

a26

b

3a22

c

3a24

d

a22

answer is D.

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Detailed Solution


0ax4a2x2 dx0ax2a2x2 dx                     Put        x =   a     sinθ           dx =   a     cosθ        
I=0π2 a4 sin4θ a cosθ.a cosθ 0π2 a2 sin2θ a cosθ a cosθ 
  =a 20π2 sin4θ cos2θ 0π2 sin2θ cos2θ   =a 2 3.1.16.4.2·π21.14.2·π2  =a22

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The value of the expression ∫0ax4a2−x2dx∫0ax2a2−x2dx