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Q.

The value of the expression C02C12+C22..+(1)nCn2 is (Here Ck=nCk

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a

0, if n is odd

b

(1)n, if n is odd

c

(1)n/2Cn/2, if n is even

d

(1)n1Cn1, if n is even

answer is A, C.

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Detailed Solution

When n is odd, take n=2m+1, so that

S=C02C12+C22..+(1)2mC2mm+(1)2m+1C2m+12=C02C2m+12C12C2m2+..+(1)mCm2Cm+12 But 2m+1C0+2m+1C2m+1 2m+1C1=2m+1C2m etc. Therefore S=0

When n is even, we take n=2 m. In this case

C02C12+C22C32+..+(1)2mC2m2= Coefficient of constant term in

C0C1x+C2x2+(1)2mC2mx2m C0+C11x+C21x2+.+C2m1x2m

= Coefficient of constant term in (1x)2m1+1x2m

= Coefficient of x2min(1x)2m(1+x)2m

= Coefficient of x2m in 1x22m

(1)m 2mCm=(1)n/2 nCn/2

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