Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5

Q.

The value of y for which the equation 15(y - 4) - 2(y - 9) + 5(y + 6) = 0 holds true is [[1]].


see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

answer is 2 3.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

detailed_solution_thumbnail
The value of y for which the equation 15(y - 4) - 2(y - 9) + 5(y + 6) = 0 holds true is 2 3 .
We have the linear equation as follows,
15(y - 4) - 2(y - 9) + 5(y + 6) = 0
We will use the distributive property of multiplication, and simplify the equation as follows,
15(y) – 15(4) – 2(y) – 2(-9) + 5(y) +5(6)
15y – 60 – 2y + 18 + 5y + 30
18y – 12 = 0
Adding 12 on both sides, we get,
18y – 12 + 12 = 0 + 12
18y = 12
Dividing by 18 on both sides, we get,
18y 18 = 12 18 y= 2 3
So, the required value of y is 2 3 .
 
Watch 3-min video & get full concept clarity

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon