Q.

The value of π2π[2sinx]dx where [.] represents the greatest integer function is 

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a

-2π

b

5π3

c

-π

d

5π3

answer is A.

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Detailed Solution

I=π2π 2 sin x dx   For  x π, 7π6 and 11π6, 2π                2 sin x=-1   For x7π6, 11π6         2 sin x=-2

  I=π7π/6 (-1) dx+7π/611π/6 (-2) dx+11π/62π (-1) dx    =(-1)π7π6+(-2)7π/611π6+(-1)ππ/62π    =-5π3

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