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Q.

The value of 3+cot80°cot20°cot80°+cot20° is

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a

tan20°

b

tan50°

c

cot50°

d

cot20°

answer is B.

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Detailed Solution

G.E. =3+cos80°cos20°sin80°sin20°cos80°sin80°+cos20°sin20°

=2sin80°sin20°+(sin80°sin20°+cos80°cos20°)sin20°cos80°+cos20°sin80°

=(cos60°cos100°)+cos60°sin100°=1cos100°sin100°=tan50°.

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