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Q.

The value of a  so that the volume of the parallelepiped formed by

i+aj+k , j+ak and  ai+k  becomes minimum is 

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a

-3

b

13

c

3

d

3

answer is C.

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Detailed Solution

detailed_solution_thumbnail

Volume of the parallelepiped is 
Va=1a101aa01=a3a+1
V'a=3a21=0 if  a=±13
V"a=6a>0 if  a=13
Thus Va  is minimum when  a=13.
 

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