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Q.

 The value of cosecxcos21+logtanx2dx is 

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a

tan1+logtanx2+C

b

sec21+logtanx2+C

c

tan1+logtanx2+C

d

sin21+logtanx2+C

answer is C.

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Detailed Solution

 Put 1+logtanx2=t dtcos2t=tant+C1sinxdx=dt =tan1+logtanx2+C

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 The value of ∫cosec⁡xcos2⁡1+log⁡tan⁡x2dx is