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Q.

The value of i^×(i^×a)+j^×(j^×a)+k^×(k^×a) is

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a

a

b

a×k^

c

-2a

d

-a

answer is C.

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Detailed Solution

Let a=a1i^+a2j^+a3k^, Then,

i^×a=i^×a1i^+a2j^+a3k^

=a2k^-a3j^

j^×a=j^×a1i^+a2j^+a3k^

=-a1k^+a3i^=a3i^-a1k^

k^×a=k^×a1i^+a2j^+a3k^

=a1j^-a2i^

Now, i^×(i^×a)+j^×(j^×a)+k^×(k^×a)

=i^×a2k^-a3j^+j^×a3i^-a1k^+k^×a1j^-a2i^

=-a2j^-a3k^-a3k^-a1i^-a1i^-a2j^

=-2a1i^+a2j^+a3k^

=-2a

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