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The value of $' k'$ , if the roots of the quadratic equation $kx (x - 2) + 6 = 0$ are equal

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Detailed Solution

$kx (x - 2) + 6 = 0 are equal roots {kx}^{2} - 2 kx + 6 = 0 b^{2} = 4 ac \Rightarrow {(- 2 k)}^{2} = 4 (k) (6) \to 4 k^{2} - 4 k (6) \to k = 6$

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