Q.

The value of Kp for the reaction, CO2(g) +C(s)2CO(g)is 3 at 1000 K. If initially Pco2=0.48 bar PCo=0 bar and pure graphite is present, calculate the equilibrium partial pressures of CO and CO2

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a

0.15 bar and 0.15 bar

b

0.66 bar and 0.66 bar

c

0.15 bar and 0.66 bar

d

0.66 bar and 0.15 bar

answer is C.

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Detailed Solution

CO2(g)+C(s)2 CO(g)

0.48                                        0 

0.48 − x                                 2x

Kp=4x20.48-x=3

x=0.33

PCO2=0.15

PCO = 0.66

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