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Q.

The value of k so that the equation  x312x+k=0 has distinct roots in [0, 2] is

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a

2

b

-2

c

none of these

d

4

answer is D.

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Detailed Solution

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If α and β are real and distinct roots of x312x+k=0. Then f(x)=x312x+k satisfies 

f(α)=f(β)=0 then there  γ[α,β][0,2] such that

f(γ)=0i.e.,  3v212=0γ=±2. Not possible.

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