Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

The value of Limxπ2sin x-(sin x)sin xsin x+log sin x is

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

2

b

1

c

-1

d

0

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Limxπ2sin x-(sin x)sin x1-sin x+log sin x     00 form   L' Hospital Rule =Limxπ2 cosx-(sin x)sin xcos x log(sin x)+cos x-cos x+cot x
=Limxπ2 1-(sin x)sin x (log sin x+1)cosec x-1      00 form=Limxπ2 -(sin x)sin x cot x-(logsin x+1)(sin x)sin x cos x(logsinx+1)-cosec x cot x =Limxπ2 (sin x)sin x+(log sin x+1)2(sin x)sin x.sin xcosec x
=1+11=2

Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring