The value of sin230°÷sin245°is

$$sin230$$°$$=(12)2=14sin245$$°$$=(12)2=12$$∴$$sin230$$°÷$$sin245$$°$$=14$$÷$$12=(14)(12)=14$$×$$21=12$$

Q.

The value of $\sin^{2} 30 ° \div \sin^{2} 45 °$ is

Moderate

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By Expert Faculty of Sri Chaitanya

$\frac{1}{2}$

$\sqrt{3}$

$\frac{1}{\sqrt{3}}$

answer is B.

(Detailed Solution Below)

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Detailed Solution

$\begin{array}{l} \sin^{2} 30 ° = {(\frac{1}{2})}^{2} = \frac{1}{4} \\ \sin^{2} 45 ° = {(\frac{1}{\sqrt{2}})}^{2} = \frac{1}{2} \\ ∴ \sin^{2} 30 ° \div \sin^{2} 45 ° = \frac{1}{4} \div \frac{1}{2} \\ = \frac{(\frac{1}{4})}{(\frac{1}{2})} = \frac{1}{4} \times \frac{2}{1} = \frac{1}{2} \end{array}$

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