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Q.

The value of sin2(5212)°sin2(2212)° is

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a

3+12

b

3+142

c

3142

d

3+14

answer is A.

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Detailed Solution

sin25212°sin22212°

=sin5212+2212sin52122212

=sin75°sin30°

=3+122×12

=3+142

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