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Q.

The value of $\tan 3 A - \tan 2 A - \tan A$ is

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a

$\tan A . \tan 2 A - \tan 2 A . \tan 3 A - \tan 3 A . \tan A$

b

$- \tan 3 A . \tan 2 A . t a n A$

c

none of these

d

$\tan 3 A . \tan 2 A . t a n A$

answer is A.

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Detailed Solution

$3 A - 2 A = A;$

$\tan (3 A - 2 A) = \tan A \frac{\tan 3 A - t a m 2 A}{1 + \tan 3 A \tan 2 A} = \tan A \tan 3 A - \tan 2 A = \tan A + \tan A \tan 2 A \tan 3 A$

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