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Q.

The values ​​of Question Imageand Question Imagefrom the given three equations Question Imageand Question Imageincrease is:


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a

Question Image

b

Question Image

c

Question Image

d

5 

answer is A.

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Detailed Solution

Concept: The above question is an example of a system of linear equations. They can be easily resolved with specific steps. You can see that there are three variables Question Image. Therefore, you need to remove one variable from both. This leaves us with two linear equations with two variables. In this way, these equations can be solved more easily  and the values ​​of Question Imagecan be calculated more easily.
 You get three equations
Question Image It's easy to see that each variable is a power of one. Therefore, these equations are simultaneous equations. Obviously, simply adding or subtracting these equations does not solve the value of each variable. The approach we  take is to take two pairs from the above three equations and remove one variable from each. Attempts to remove the variable z using  equations 1 and 2. Therefore, subtract Question Image Question Image Question Image Again, we use expressions 2 and 3 to try to remove the variable z.  Therefore, add Question Image (2) and (3)
Question ImageYou now have a system of equations for the two variables (4) and (5) . These equations can be easily solved  by deleting one variable
Question Image Therefore, Question Image Question Image And in Equation 1
Question ImageThe values ​​of the variables Question Imageand Question Imageare all Question ImageHence, the answer is option 1.
 
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