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The values $\land_{m}^{\infty}$ for $N H_{4} C l, N a O H$ and $N a C l$ respectively 149.74, 248.1 and $126.4 o h m^{- 1} c m^{2} m o l^{- 1}$ . The value of $\land_{m}^{\infty}$ of $N H_{4} O H$

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143.2

71.44

271.44

371.44

answer is B.

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Detailed Solution

$N H_{4} C l + N a O H \to N H_{4} O H + N a C l$

$\land_{N H_{4} O H} = (149.74 + 248.1) - 126.4 = 271.44$

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