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Q.

The values of electronegativity of atoms A and B are 1.20 and 4 respectively. The percentage ionic character of A-B bond is :

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a

43.0%

b

60% 

c

 66.3% 

d

72.2% 

answer is B.

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Detailed Solution

A formula for calculating ionic character is as follows:

% ionic character=16EAEB+3.5EAEB2

% ionic character=16[41.2]+3.5[41.2]2

% ionic character=72.24.

Hence, the option B is correct.

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