The values of equivalent conductivity at infinte dilutions for NH₄Cl, NaOH and NaCl are respectively 149.74, 248.1 and 126.4 ohm^–1 cm² ${\text{ equi }}^{-1}\text{. The value of }{\mathrm{\lambda }}^{\mathrm{\infty }}\text{ eq of }{\mathrm{NH}}_4\mathrm{OH}\text{ is }$ 

According to Kohlrausch's law of equivalent conductivity, it could be stated:

$$\begin{gathered} {\wedge }_{N{H}_{4}OH}^o={\wedge }_{NH4Cl}^o+\hspace{0.17em}{\wedge }_{NaOH}^o- {\wedge }_{NaCl}^o \\ = 149.74+248.1-126.4 \\ =271.44 oh{m}^{-1}.c{m}^{2}e{q}^{-1.} \end{gathered}$$