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The values of IE(I), IE(II), IE(III) and IE(IV) of an atom are respectively 7.5 eV, 25.6 eV, 48.6 eV and 170.6 eV. The electronic configuration of the atom will be:

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$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}$

$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{1}$

$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{3}$

$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2}$

answer is B.

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Detailed Solution

First, let's get the data from equation

So, from the data,

Ip, was small, then difference between IP₁ and IP₂and the IP₂and IP₃ was also small (little bit mover than IP1) , but the difference between IP₃ and IP₄ was large (122eV).

so the electronic configuration 1s²2s²2p⁶3s²3p¹ is the difference between IP₃and IP₄

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