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Q.

The values of Plank’s constant is 6.63×10−34Js. The velocity of light is3.0×108m    S−1 . Which value is closest to the wavelength in nanometers of a quantum of light with frequency of 8×1015 S−1?

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a

2×10−25

b

4×101

c

3×107

d

5×10−18

answer is B.

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Detailed Solution

E=hυ=chλ;and  υ=cλ

8×1015=3.0×108λ

∴ λ =3.0×1088×1015=0.37×10−27=37.5×10−9m=4×101nm

 

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