The values of Plank’s constant is 6.63×10−34Js. The velocity of light is3.0×108m S−1 . Which value is closest to the wavelength in nanometers of a quantum of light with frequency of 8×1015 S−1?

E=hυ=chλ;and υ=cλ8×1015=3.0×108λ∴ λ =3.0×1088×1015=0.37×10−27=37.5×10−9m=4×101nm

The values of Plank’s constant is 6.63×10−34Js. The velocity of light is3.0×108m S−1 . Which value is closest to the wavelength in nanometers of a quantum of light with frequency of 8×1015 S−1?

E=hυ=chλ;and υ=cλ8×1015=3.0×108λ∴ λ =3.0×1088×1015=0.37×10−27=37.5×10−9m=4×101nm

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The values of Plank’s constant is $6.63 \times 10^{- 34} J s$ . The velocity of light is $3.0 \times 10^{8} m S^{- 1}$ . Which value is closest to the wavelength in nanometers of a quantum of light with frequency of $8 \times 10^{15} S^{- 1}$ ?

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$2 \times 10^{- 25}$

$4 \times 10^{1}$

$3 \times 10^{7}$

$5 \times 10^{- 18}$

answer is B.

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Detailed Solution

$E = h υ = \frac{c h}{λ}; a n d υ = \frac{c}{λ}$

$8 \times 10^{15} = \frac{3.0 \times 10^{8}}{λ}$

$∴ λ = \frac{3.0 \times 10^{8}}{8 \times 10^{15}} = 0.37 \times 10^{- 27} = 37.5 \times 10^{- 9} m = 4 \times 10^{1} n m$

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The values of Plank’s constant is 6.63×10−34Js. The velocity of light is3.0×108m S−1 . Which value is closest to the wavelength in nanometers of a quantum of light with frequency of 8×1015 S−1?

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The values of Plank’s constant is $6.63 \times 10^{- 34} J s$ . The velocity of light is $3.0 \times 10^{8} m S^{- 1}$ . Which value is closest to the wavelength in nanometers of a quantum of light with frequency of $8 \times 10^{15} S^{- 1}$ ?