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The values of x and y which satisfy the equations: 47x + 31y = 63 and 31x + 47y = 15 are __________________

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-2 and -1

2 and 1

-2 and 1

2 and -1

answer is D.

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Detailed Solution

Pair of linear equations (Given):

47x + 31y = 63 ---------------------(1)

31x + 47y = 15 ---------------------(2)

Multiply the equation (1) by 31 and the equation (2) by 47 and,

By Subtracting (2) from (1) we get......

(961 - 2209)y = 63 × 31- 15 × 47

-1248y = 1953 - 705

-1248y = 1248

So, y = -1

Substitute y = -1 in equation (1) we get.......

47x = 94

So, x = 2

Thus, -1 and 2 are the values of y and x.

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