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Q.

The values of 'θ' satisfying sin7θ=sin4θsinθ in 0<θ<π2 are

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a

π6,π4

b

π3,π9

c

π3,π4

answer is A.

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Detailed Solution

sin7θ=sin4θsinθsin7θ+sinθ=sin4θ2sin4θ.cos3θ=sin4θsin4θ[2cos3θ1]=0sin4θ=0 orcos3θ=12

sin4θ=sinπ or cos3θ=cosπ34θ=π or 3θ=π3θ=π4 or θ=π9

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