The van der Waal’s parameters of two gases are given as
Considering the value of parameter, which of the following statements is/are correct

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Critical volume of A < critical volume of B

Critical pressure of A > critical pressure of B

Critical temperature of A < critical temperature of B

Ease of liquification of A > ease of liquification of B

answer is A, C.

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Detailed Solution

Gas ‘A’

$V_{c} = 3 b 3 \times 6.5 = 19.5 d m^{3} m o l^{- 1}; P_{c} = \frac{a}{27 b^{2}} \frac{6.5}{2 \times {(0.056)}^{2}} = 76.8 a t m$

$T_{c} = \frac{8 a}{27 R b} \frac{8 \times 6.5}{27 \times 0.0821 \times 0.056} = 418.9 K$

$G a s' B'$

$P = \frac{n R T}{V} = \frac{(11.36 m o l) (0.08206 \frac{L . a t m}{K . m o l}) (700 K)}{(0.800 L)}; V_{c} = 3 b = 816 a t m 18 \times 6.5 = 1170 d m^{3} m o l^{- 1}$ $P_{c} = \frac{a}{27 b^{2}} \Rightarrow \frac{18}{27 \times {(0.011)}^{2}} = 5509.6 a t m; T_{c} = \frac{8 a}{27 R b} \frac{8 \times 18}{27 \times 0.0821 \times 0.11} = 5905.6 K$ Higher the critical temperature greater the ease of liquefaction.