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Q.

The vapor pressure of a solvent decreased by 10 mm of Hg when a non-volatile solute was added to the solvent. The mole fraction of solute in the solution is 0.2. What would be the mole fraction of solvent if decrease in vapor pressure is 20 mm?

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a

0.6

b

0.8

c

0.2

d

0.4

answer is B.

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Detailed Solution

$\frac{P^{o} - P}{P^{o}} = X_{2}$

$\frac{10}{P^{o}} = 0.2 \Rightarrow P^{o} = 50$

$Now \frac{50 - 30}{50} = X_{2}$

$\Rightarrow x_{2} = 1 - 0.4$

=0.6

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The vapor pressure of a solvent decreased by 10 mm of Hg when a non-volatile solute was added to the solvent. The mole fraction of solute in the solution is 0.2. What would be the mole fraction of solvent if decrease in vapor pressure is 20 mm?