The vapour density of a gas is 11.2. The volume occupied by 10g of the gas at STP is

$$\begin{gathered} vapour density=11.2 \\ let\text{'}s find molar mass molar mass=2\times 11.2 =22.4 \\ no.of moles=10÷22.4=0.45 moles \\ so the volume occupied by 10 g of gas is 0.45\times 22.4=10 l \end{gathered}$$