The vapour density of a volatile chloride of a metal is 59.5 and the equivalent mass of the metal is 24. The atomic mass of the element will be

$$\begin{gathered} \mathrm{Molar} \mathrm{mass} \mathrm{of} \mathrm{chloride}=2\times \mathrm{VapourDensity} \\ \mathrm{Molar} \mathrm{mass} \mathrm{of} \mathrm{chloride}=2\times 59.5 \\ \mathrm{Molar} \mathrm{mass} \mathrm{of} \mathrm{chloride}=119...\left(1\right) \end{gathered}$$

Relation between equivalent mass and molar mass is determined as:

(Assume that molar mass is x and n-factor is n)

$$\begin{gathered} \mathrm{Equivalent} \mathrm{mass}=\frac{\mathrm{Molar} \mathrm{mass}}{\mathrm{n}-\mathrm{factor}} \\ 24=\frac{\mathrm{x}}{\mathrm{n}} \end{gathered}$$

Substitute above relation into equation 1,

$$\begin{gathered} 35.5\times \mathrm{n}+24\times \mathrm{n}=119 \\ \mathrm{n}=2 \end{gathered}$$

Value of x is calculated as:

$$\begin{gathered} 24=\frac{\mathrm{x}}{2} \\ \mathrm{x}=48 \end{gathered}$$
Molar mass of element =48 g/mol