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The vapour density of undecomposed $N_{2} O_{4}$ is 46. When heated, vapour density decreases to 24.5 at equilibrium due to its dissociation to ${NO}_{2}$ . The percent dissociation of $N_{2} O_{4}$ at equilibrium is equal to

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answer is D.

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Detailed Solution

\% \alpha = \frac{{D - d}}{{d\left( {n - 1} \right)}} \times 100

{N_2}{O_4}\leftrightharpoons 2N{O_2}\;\;n\;=2

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